问题补充：
求z=yarctan(y/x)的全微分,dz/dx,dz/du- =打错，是dz/dy
答案：
Z‘x=(-y^2/x^2)/(1+y^2/x^2)=-y^2/(x^2+y^2)
Z‘y=arctan(y/x)+xy/(x^2+y^2)
dz=[-y^2/(x^2+y^2)]dx+[arctan(y/x)+xy/(x^2+y^2)]dy
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时间：2024-04-15 02:42:00
求z=yarctan(y/x)的全微分,dz/dx,dz/du- =打错，是dz/dy
Z‘x=(-y^2/x^2)/(1+y^2/x^2)=-y^2/(x^2+y^2)
Z‘y=arctan(y/x)+xy/(x^2+y^2)
dz=[-y^2/(x^2+y^2)]dx+[arctan(y/x)+xy/(x^2+y^2)]dy
2019-08-27
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2024-07-15
![z=(x+y)/(x-y) dz=?已知[(x+ay)dx+(ax+y)dy]/(x+y)²](https://900zi.500zi.com/uploadfile/img/9/558/04a993a39bf9bb207731b1b850528e57.jpg)
