问题补充:
若m减去n等于2,m乘以n等于负1,求(负2乘以m乘以n加上2乘以m加上3乘以n)减去(3乘以m乘以n加上2乘以n减去2乘以m)减去(m加上4乘以n加上m乘以n)的值.非常急)
答案:
(-2*m*n+2*m+3*n)-(3*m*n+2*n-2*m)-(m+4*n+m*n)
=-2mn+2m+3n-3mn-2n+2m-m-4n-mn
=-2mn-3mn-mn+2m+2m-m+3n-2n-4n
=-6mn+3m-3n 当m-n=2,mn=-1时 -6mn+3m-3n=6+6=12
答案不确定对,但还是希望可以帮到你
======以下答案可供参考======
供参考答案1:
化解得原式=3(m-n-2mn)=12