问题补充:
(c-2ab+a+b)(a-2+b+c)+(1-ab)^2因式分解急
答案:
(c-2ab+a+b)(a-2+b+c)+(1-ab)^2
=(a+b+c-2ab)(a+b+c-2)+(1-ab)^2
=(a+b+c)^2-2(1+ab)(a+b+c)+4ab+(1-ab)^2
=(a+b+c)^2-2(1+ab)(a+b+c)+(1+ab)^2
=[(a+b+c)-(1+ab)]^2
=(a+b+c-1+ab)^2
时间:2024-01-27 02:14:27
(c-2ab+a+b)(a-2+b+c)+(1-ab)^2因式分解急
(c-2ab+a+b)(a-2+b+c)+(1-ab)^2
=(a+b+c-2ab)(a+b+c-2)+(1-ab)^2
=(a+b+c)^2-2(1+ab)(a+b+c)+4ab+(1-ab)^2
=(a+b+c)^2-2(1+ab)(a+b+c)+(1+ab)^2
=[(a+b+c)-(1+ab)]^2
=(a+b+c-1+ab)^2