php匹配字符串中的url并替换为超链接

function replaceUrls($str){if(empty($str)){return $str;}$regex = '/(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|])/i';return preg_replace($regex,'<a href="$1">$1</a>',$str);}

参考链接：/lw5116/p/10872090.html