转载http://m./qq_38125123/article/details/74910784
表单及点击提交事件report-submit设置为true时返回 formId 用于发送模板消息
<form report-submit='true' bindsubmit="formSubmit"> <button class='login-user'form-type='submit' data-name='个人信息'> <imageclass="orders-image"src="../../image/s_dzl11.png"></image> <text class="orders-text">个人信息</text> </button> </form>
/*修改按钮样式，使其能够包裹其他组件*/
.login-user{ border:none; text-align:left; padding:0; margin:0; line-height:1.5; background-color: #FFF; }
// 获取fromId formSubmit: function (e) { var that = this var formId = e.detail.formId; var content = e.detail.target.dataset.name; console.log('form发生了submit事件，推送码为：', formId) console.log('button点击事件来自：', content) },
