问题:判断两个数组是否存在相同元素

今天做一个数组添加操作,,但是要判断数据是否重复,,,头脑第一个想法就是遍历两个数组查询是否有重复,

然后就吧啦吧啦.....一通狂敲,如下:

1 boolean has = false; 2 String[] strOne= {"c","b","a","d"}; 3 String[] strTwo= {"a","b","d","g"}; 4 for (int i = 0; i < strOne.length; i++) { 5 if (ArrayUtils.contains(strTwo, strOne[i])) { 6has = true; 7break; 8 } 9 }10 11 System.out.println(has )12 13

写完之后莫名的不爽,我要到循环里面进行判断..........

然后在分析问题 ,判断两个数组是否存在相同元素 .........咦------倒吸一口冷气,这丫的不就是求交集么

交集的函数不就是retainAll

然后马上开始吧啦吧啦.......一通狂敲,如下:

1boolean has = false;2String[] strOne= {"c","b","a","d"};3String[] strTwo= {"a","b","d","g"};4HashSet<String> set = new HashSet<>(Arrays.asList(strOne));5set.retainAll(Arrays.asList(strTwo));6if(set.size() > 0){7 has = true;8}

虽然一个九行一个八行 ,, 但是需要我们好好想一下,,,如果问题再复杂一下呢?

一.条条大路通罗马,,,分析问题,,,找到最优

二.一些基础函数不用难免忘记