独角兽企业重金招聘Python工程师标准>>>
我想用英语写注释，麻痹，写不明白！
编译器是vc++6.0
输入：omnia gallia est
密钥：3
加密：RPQLD JDOOLD HVW
#include <stdio.h>
int str_len(char *str)//计算字符串长度
{
int len = 0;//设置长度初始值为0
while(*(str++))//用指针递增指向下一个内容直到空为止
len++;//记数
return len; //返回记录的数
}
int main(int argc, char *argv[])
{
//不懂阿斯科马 就把字母存放在数组中了
char a[26] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
char b[26] = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
char str[50];//定义一个接收输入字符串的数组
int k;
printf("Please input the words :");
gets(str);// 得用gets 有空格 好使
printf("Please input your number:");
scanf("%d",&k);//输入密钥
int len = str_len(str);
/*代码主体两个循环，一层循环控制输入字符，一个一个取出来
与字母表对照，找到位置，再用密钥找出对应的大写字母*/
for(int i = 0;i<len;i++)
for(int j = 0;j<26;j++)
{
if(str[i]==a[j])
str[i] = b[(j+k)%26];
else
str[i] = str[i];
}
printf("%s\n",str);//输出字符串
return 0;
}
//解密
#include <stdio.h>
int str_len(char *str)
{
int len = 0;
while(*(str++))
len++;
return len;
}
int main(int argc, char *argv[])
{
char a[26] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
char b[26] = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
char str[50];
int k;
printf("Please input the words :");
gets(str);
printf("Please input your number:");
scanf("%d",&k);
int len = str_len(str);
for(int i = 0;i<len;i++)
for(int j = 0;j<26;j++)
{
if(str[i]==b[j])
str[i] = a[(j+26-k)%26];
else
str[i] = str[i];
}
printf("%s\n",str);
return 0;
}
