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php单表显示动态下拉框 PHP:使用optgroup动态下拉列表

时间:2020-01-01 18:32:28

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php单表显示动态下拉框 PHP:使用optgroup动态下拉列表

我正在开发一个下拉菜单,该菜单使用HTML optgroups作为员工所属的组名。这是MySQL查询和输出:

mysql> SELECT employee.emp_id,employees.empname,employees.grp_id,groups.groupname FROM雇员离开的雇员加入员工组。grp_id= groups.grp_id,按组名asc排序;

+ -------- + ------------ + -------- + ----------- +

| emp_id | empname | grp_id | 组名|

+ -------- + ------------ + -------- + ----------- +

| 20 | 员工2 | 13 | 第1组|

| 19 | 员工1 | 13 | 第1组|

| 21 | 员工3 | 14 | 第2组|

+ -------- + ------------ + -------- + ----------- +

设置3行(0.00秒)

唯一的问题是,我很难确定如何使optgroup正常工作。我尝试了无数次,这真的开始让我感到沮丧。 以下是我想要的输出示例(示例):

Employee 2

Employee 1

Employee 3

基本上,optgroup必须是“ groupname”,选项“ name”应该是“ emp_id”,而动作“ option”(下拉项)是“

empname”。

我希望这是可以做的,但是真的不确定。这是我所拥有的功能,但无法正常运行:

function getDynGrpList() {

global $db;

// $query = "SELECT * FROM employees ORDER BY grp_id desc;";

$query = "SELECT employees.emp_id,employees.empname,employees.grp_id,groups.groupname FROM employees left join groups on employees.grp_id = groups.grp_id order by groupname asc;";

$employees = $db->GetAll($query);

$groups = array();

while ($qa = $employees->GetRows()) {

$groups[$qa['groupname']][$qa['grp_id']] = $qa['empname'];

}

foreach ($groups as $label => $opt) { ?>

foreach ($groups[$label] as $id => $name) { ?>

从凌晨3:15 CST(2/27)开始的getDynGrpList函数:

function getDynGrpList() {

global $db;

// $query = "SELECT * FROM employees ORDER BY grp_id desc;";

$query = "SELECT employees.emp_id,employees.empname,employees.grp_id,groups.groupname FROM employees left join groups on employees.grp_id = groups.grp_id order by groupname asc;";

$employees = $db->GetAll($query);

$groups = array();

while ($qa = $employees->GetRows()) {

$groups[$qa['groupname']][$qa['emp_id']] = $qa['empname'];

}

var_export($groups);

foreach($groups as $label => $opt): ?>

<?php foreach ($opt as $id => $name): ?>

}

最终解决方案(在Felix Kling的帮助下)

function getDynGrpList() {

global $db;

$query = "SELECT employees.emp_id,employees.empname,employees.grp_id,groups.groupname FROM employees left join groups on employees.grp_id = groups.grp_id order by groupname asc;";

$employees = $db->GetAll($query);

$groups = array();

foreach ($employees as $employee) {

$groups[$employee['groupname']][$employee['emp_id']] = $employee['empname'];

}

foreach($groups as $label => $opt): ?>

<?php foreach ($opt as $id => $name): ?>

}

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