后端开发|php教程

quot,gt,title,lt,query

后端开发-php教程

HI,我是一个PHP新手，今天一个问题折腾了一上午，请大家帮我看一下，万分感谢

PHP code

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Book-O-Rama Book Entry Result

<?php //create short variable names $isbn = $_POST[isbn]; $author = $_POST[author]; $title = $_POST[ itle]; $price = $_POST[price];if ( !$isbn || !$author || !$title || !$price ) { echo "You have not entered all the required details.

"."Please go back and try again."; exit; } if ( !get_magic_quotes_gpc() ) { $isbn = addslashes($isbn); $author = addslashes($author); $title = addslashes($title); $price = doubleval($price); }@ $db = new mysqli(localhost, ookorama, ookorama123, ooks); if ( mysqli_connect_errno() ) { echo "Error: Could not connect to database. Please try again later."; exit; }$query = "insert into books values ($isbn, $author, $title, $price)or die(mysql_error())";;echo $query;$result = $db->query($query);if ( $result ) { echo mysqli_affected_rows." book inserted into database."; } else { echo mysql_errno()."".mysql_error(); echo "An error has occurred.The item was not added."; }$db->close(); ?>

这是来自PHP和 MySQL web开发（第四版）中的一段代码。

我想问的是为什么最后总是输出An error has occurred.The item was not added

而且插入结果$result = -1

请大家指点一下

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——解决方案——————–

$query = “insert into books values (‘$isbn’, ‘$author’, ‘$title’, ‘$price’)”;

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echo $query;

$result = $db->query($query) or die($db->error);